12x^2-16x=16

Solution for 12x^2-16x=16 equation:

12x^2-16x=16

We move all terms to the left:

12x^2-16x-(16)=0

a = 12; b = -16; c = -16;
Δ = b2-4ac
Δ = -162-4·12·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*12}=\frac{-16}{24}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*12}=\frac{48}{24}
=2
$